# Applied Differential Equations by Murray R. Spiegel By Murray R. Spiegel

This quantity prepares readers to translate mathematically utilized difficulties into the language of differential equations, clear up these differential equations topic to given stipulations bobbing up within the difficulties, and interpret the ideas received.

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Summarize procedure. Consider to Mdx + Ndy = Compute ox dy If (1) = If (1) ^ the equation (2), compute (2), is (1) exact and can easily be solved. minus (2), divided by A''; call the result /. If/ is a function of x alone, then e^^'^' is an integrating factor. If not, compute (2) minus (1), divided by M; call the result g. If ^ is a function of >^ alone, then an integrating factor. e^^'^" is Illustrative Example 1 Solve y dx + Here Solution. 1 Now - 3 3-1 But y 3x = M =y, (3 + 3x - y)dy = N= dM dN ay dx 3 -\- 3x 3 - y is 2 - y is not a function of x alone.

Cgfi"^ Ixy = — e. 4x. -\- y tan y" —y = j' = (7 + x 0. j(-) = 4. {yiO)=i, 4x. \yXO) x)j{,y - x). = 0. >'(-2)=3. : Sec. V Differential Equations in General (d) y = (e) xy- Ci - CoX = Ax - + = 0. x{y'f -f y'" C3X-. B. 2yy' + 23 = xyy" 0. \y'0) Find a 3. differential = 2. equation for each of the following families of curves in the xy plane with center at the origin and any radius, (b) All parabolas (a) All circles through the origin with x axis as common ^ = (d) All ellipses with center at the origin and tangent to the y axis, axes on the coordinate axes.

But how can we tell that l/j^ is an integrating factor? Let us above that Ijy^ is makes equation this factor consider this general problem. Consider the case where M dx ~ N dy = is not exact or separable. Let us multiply our equation by the integrating factor fx (as yet unknown). is By definition of an integrating factor, the equation fiM dx -f fxN dy = now exact, so that ^{f^M) We shall simplify Case I. v alone. write (8) as dM dN ^d/j, dy dx dx dju IX (dM N\dy \ dN\ dx/ First-Order and Simple Higher-Order Equations 40 of dx on the right side of If the coefficient f(x)] then we have =f{x)dx and d/nj/j, In = // Case dN\ — [dM 1 — — If IT.